kb: used $.distinct[tables]

R. Averkov 04.02.2006 15:42 / 04.02.2006 16:24

$salary[^table::sql{
	SELECT employee_ord, month, salary
	...
	WHERE
	year=2005
}]

$salary[^salary.hash[employee_ord;$.distinct[tables]]]

^for[employee_i](1;$employee_list){

	<employee ord="$employee_i">
	
		$_salary[$salary.$employee_i]
		
		^_salary.menu{
		
			<month no="$_salary.month"
			salary="$_salary.salary"/>
		
		}
	
	</employee>
}